0=130x+2000+40x+x^2

Solution for 0=130x+2000+40x+x^2 equation:

0=130x+2000+40x+x^2

We move all terms to the left:

0-(130x+2000+40x+x^2)=0

We add all the numbers together, and all the variables

-(130x+2000+40x+x^2)=0

We get rid of parentheses

-x^2-130x-40x-2000=0

We add all the numbers together, and all the variables

-1x^2-170x-2000=0

a = -1; b = -170; c = -2000;
Δ = b2-4ac
Δ = -1702-4·(-1)·(-2000)
Δ = 20900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20900}=\sqrt{100*209}=\sqrt{100}*\sqrt{209}=10\sqrt{209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-10\sqrt{209}}{2*-1}=\frac{170-10\sqrt{209}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+10\sqrt{209}}{2*-1}=\frac{170+10\sqrt{209}}{-2}
$